Figure 3 shows a modification of the first example in section 2.7.
[1]--.--(2)
a |
22 | 12
12 | 12
Figure 3 |
.------+------.
| | |
(6)--.--[3] [4] |
| a |
13 | 12 22 |
12 | 22 12 |
| |
.-------. |
| | |
[7] (8)-----.-----(5)
a | a
13 u | 12
22 u | 22
|
(9)
a
11
12
If we choose to break the loop at individual 5 in figure 3, we
replace that pedigree with the one shown in figure 4, where 10 is
the duplicate of 5.
[1]--.--(2)
a |
22 | 12
12 | 12
Figure 4 |
.------+------.
| | |
(6)--.--[3] [4] (10)
| a a
13 | 12 22 12
12 | 22 12 22
|
.-------.
| |
[7] (8)-----.-----(5)
a | a
13 u | 12
22 u | 22
|
(9)
a
11
12
The PEDFILE then becomes:
1 1 0 0 3 0 0 1 1 2 0 1 0 1 1 Ped: 1 Per: 1 1 2 0 0 3 0 0 2 0 1 1 1 0 1 1 Ped: 1 Per: 2 1 3 1 2 7 4 4 1 0 2 1 1 0 0 1 Ped: 1 Per: 3 1 4 1 2 0 5 5 1 0 1 0 1 0 1 1 Ped: 1 Per: 4 1 5 0 0 9 0 0 2 2 2 1 1 0 0 1 Ped: 1 Per: 5 1 10 1 2 0 0 0 2 2 2 1 1 0 0 1 Ped: 1 Per: 5 1 6 0 0 7 0 0 2 0 1 1 0 1 1 1 Ped: 1 Per: 6 1 7 3 6 0 8 8 1 0 2 1 0 1 0 1 Ped: 1 Per: 7 1 8 3 6 9 0 0 1 0 1 0 0 0 0 0 Ped: 1 Per: 8 1 9 8 5 0 0 0 2 0 2 1 0 0 1 1 Ped: 1 Per: 9where 2 is entered into the proband field for both 5 and 10. When the loop is broken at the "proband," a 1 is entered into the proband field for one of the duplicates, e.g.:
1 1 0 0 3 0 0 1 0 2 0 1 0 1 1 Ped: 1 Per: 1 1 2 0 0 3 0 0 2 0 1 1 1 0 1 1 Ped: 1 Per: 2 1 3 1 2 7 4 4 1 0 2 1 1 0 0 1 Ped: 1 Per: 3 1 4 1 2 0 5 5 1 0 1 0 1 0 1 1 Ped: 1 Per: 4 1 5 0 0 9 0 0 2 1 2 1 1 0 0 1 Ped: 1 Per: 5 1 10 1 2 0 0 0 2 2 2 1 1 0 0 1 Ped: 1 Per: 5 1 6 0 0 7 0 0 2 0 1 1 0 1 1 1 Ped: 1 Per: 6 1 7 3 6 0 8 8 1 0 2 1 0 1 0 1 Ped: 1 Per: 7 1 8 3 6 9 0 0 1 0 1 0 0 0 0 0 Ped: 1 Per: 8 1 9 8 5 0 0 0 2 0 2 1 0 0 1 1 Ped: 1 Per: 9